Minggu, 20 September 2026
18:36 WIB
TERKINI
Cek Fakta Kiat Cerdas Deteksi Hoaks: Hindari Jebakan Berita Palsu di Media Sosial Cek Fakta Waspada! Penipuan Undian Berhadiah Catut Nama BNI Kembali Marak Climate BMKG Ungkap Potensi Hujan Lebat Landa Sejumlah Wilayah Indonesia Pekan Ini Moto Gp Veda Ega Peringkat 16 FP2 Moto3 Austria, Hakim Danish Tembus Empat Besar Moto Gp Drama Kualifikasi Moto3 Austria: Veda Ega ke-19, Uriarte Pecahkan Rekor Hukum Selebgram JP Terjerat Vape Narkoba: Stres Picu Konsumsi Etomidate Golongan II Arsip Mengenang Multatuli: Kisah 84 Hari yang Mengukir Sejarah Lebak Arsip Max Havelaar di Sekolah Belanda: Antara Pedoman dan Kebebasan Memilih Megapolitan Aroma Tak Sedap Ganggu Pejalan Kaki Dekat Halte IRTI Monas Tren Trump Larang CNN, MS NOW, Politico dari Gedung Putih: Konflik Media Memuncak Cek Fakta Kiat Cerdas Deteksi Hoaks: Hindari Jebakan Berita Palsu di Media Sosial Cek Fakta Waspada! Penipuan Undian Berhadiah Catut Nama BNI Kembali Marak Climate BMKG Ungkap Potensi Hujan Lebat Landa Sejumlah Wilayah Indonesia Pekan Ini Moto Gp Veda Ega Peringkat 16 FP2 Moto3 Austria, Hakim Danish Tembus Empat Besar Moto Gp Drama Kualifikasi Moto3 Austria: Veda Ega ke-19, Uriarte Pecahkan Rekor Hukum Selebgram JP Terjerat Vape Narkoba: Stres Picu Konsumsi Etomidate Golongan II Arsip Mengenang Multatuli: Kisah 84 Hari yang Mengukir Sejarah Lebak Arsip Max Havelaar di Sekolah Belanda: Antara Pedoman dan Kebebasan Memilih Megapolitan Aroma Tak Sedap Ganggu Pejalan Kaki Dekat Halte IRTI Monas Tren Trump Larang CNN, MS NOW, Politico dari Gedung Putih: Konflik Media Memuncak

Tabel integral

artikel daftar Wikimedia

Artikel ini berisi tentang sebagian besar integral tak tentu dalam kalkulus. Untuk daftar integral tertentu, lihat Daftar integral tertentu.
Kalkulus

Pengintegralan atau integrasi merupakan operasi dasar dalam kalkulus integral. Operasi lawannya, turunan, mempunyai kaidah yang dapat menurunkan fungsi dengan bentuk yang lebih mudah menjadi fungsi dengan bentuk yang lebih rumit. Sayangnya, integral tidak mempunyai kaidah yang dapat menghitung sebaliknya, sehingga sering kali diperlukan tabel yang memuat kumpulan integral.

Berikut adalah daftar yang memuat integral atau antiturunan yang paling umum dijumpai. Pada daftar di bawah ini, C {\displaystyle C} {\displaystyle C} mengartikan konstanta sembarang.


Daftar integral

Daftar integral yang lebih detail dapat dilihat pada halaman-halaman berikut


Aturan integrasi dari fungsi-fungsi umum

  1. ∫ a f ( x ) d x = a ∫ f ( x ) d x ( a  konstan) {\displaystyle \int af(x)\,dx=a\int f(x)\,dx\qquad {\mbox{(}}a{\mbox{ konstan)}}\,\!} {\displaystyle \int af(x)\,dx=a\int f(x)\,dx\qquad {\mbox{(}}a{\mbox{ konstan)}}\,\!}
  2. ∫ [ f ( x ) + g ( x ) ] d x = ∫ f ( x ) d x + ∫ g ( x ) d x {\displaystyle \int [f(x)+g(x)]\,dx=\int f(x)\,dx+\int g(x)\,dx} {\displaystyle \int [f(x)+g(x)]\,dx=\int f(x)\,dx+\int g(x)\,dx}
  3. ∫ f ( x ) g ( x ) d x = f ( x ) ∫ g ( x ) d x − ∫ [ f ′ ( x ) ( ∫ g ( x ) d x ) ] d x {\displaystyle \int f(x)g(x)\,dx=f(x)\int g(x)\,dx-\int \left[f'(x)\left(\int g(x)\,dx\right)\right]\,dx} {\displaystyle \int f(x)g(x)\,dx=f(x)\int g(x)\,dx-\int \left[f'(x)\left(\int g(x)\,dx\right)\right]\,dx}
  4. ∫ [ f ( x ) ] n f ′ ( x ) d x = [ f ( x ) ] n + 1 n + 1 + C (untuk  n ≠ − 1 ) {\displaystyle \int [f(x)]^{n}f'(x)\,dx={[f(x)]^{n+1} \over n+1}+C\qquad {\mbox{(untuk }}n\neq -1{\mbox{)}}\,\!} {\displaystyle \int [f(x)]^{n}f'(x)\,dx={[f(x)]^{n+1} \over n+1}+C\qquad {\mbox{(untuk }}n\neq -1{\mbox{)}}\,\!}
  5. ∫ f ′ ( x ) f ( x ) d x = ln ⁡ | f ( x ) | + C {\displaystyle \int {f'(x) \over f(x)}\,dx=\ln {\left|f(x)\right|}+C} {\displaystyle \int {f'(x) \over f(x)}\,dx=\ln {\left|f(x)\right|}+C}
  6. ∫ f ′ ( x ) f ( x ) d x = 1 2 [ f ( x ) ] 2 + C {\displaystyle \int {f'(x)f(x)}\,dx={1 \over 2}[f(x)]^{2}+C} {\displaystyle \int {f'(x)f(x)}\,dx={1 \over 2}[f(x)]^{2}+C}

Integral fungsi sederhana

Konstanta C sering digunakan untuk konstanta sembarang dalam integrasi. Konstanta ini hanya dapat ditentukan jika suatu nilai integral pada beberapa titik sudah diketahui. Jadi, setiap fungsi mempunyai jumlah integral tidak terbatas.

Rumus-rumus berikut hanya menyatakan dalam bentuk lain pernyataan-pernyataan dalam tabel turunan.


Fungsi rasional

∫ d x = x + C {\displaystyle \int \,dx=x+C} {\displaystyle \int \,dx=x+C}
∫ x n d x = x n + 1 n + 1 + C  jika  n ≠ − 1 {\displaystyle \int x^{n}\,dx={\frac {x^{n+1}}{n+1}}+C\qquad {\mbox{ jika }}n\neq -1} {\displaystyle \int x^{n}\,dx={\frac {x^{n+1}}{n+1}}+C\qquad {\mbox{ jika }}n\neq -1}
∫ ( a x + b ) n d x = ( a x + b ) n + 1 a ( n + 1 ) + C  jika  n ≠ − 1 {\displaystyle \int (ax+b)^{n}\,dx={\frac {(ax+b)^{n+1}}{a(n+1)}}+C\qquad {\mbox{ jika }}n\neq -1} {\displaystyle \int (ax+b)^{n}\,dx={\frac {(ax+b)^{n+1}}{a(n+1)}}+C\qquad {\mbox{ jika }}n\neq -1}
∫ d x x = ln ⁡ | x | + C {\displaystyle \int {dx \over x}=\ln {\left|x\right|}+C} {\displaystyle \int {dx \over x}=\ln {\left|x\right|}+C}
∫ d x a 2 + x 2 = 1 a arctan ⁡ x a + C {\displaystyle \int {dx \over {a^{2}+x^{2}}}={1 \over a}\arctan {x \over a}+C} {\displaystyle \int {dx \over {a^{2}+x^{2}}}={1 \over a}\arctan {x \over a}+C}

Fungsi irrasional

∫ d x a 2 − x 2 = arcsin ⁡ x a + C {\displaystyle \int {dx \over {\sqrt {a^{2}-x^{2}}}}=\arcsin {x \over a}+C} {\displaystyle \int {dx \over {\sqrt {a^{2}-x^{2}}}}=\arcsin {x \over a}+C}
∫ − d x a 2 − x 2 = arccos ⁡ x a + C {\displaystyle \int {-dx \over {\sqrt {a^{2}-x^{2}}}}=\arccos {x \over a}+C} {\displaystyle \int {-dx \over {\sqrt {a^{2}-x^{2}}}}=\arccos {x \over a}+C}
∫ d x a 2 + x 2 = 1 a arctan ⁡ x a + C {\displaystyle \int {dx \over a^{2}+x^{2}}={1 \over a}\arctan {x \over a}+C} {\displaystyle \int {dx \over a^{2}+x^{2}}={1 \over a}\arctan {x \over a}+C}
∫ − d x a 2 + x 2 = 1 a arccot ⁡ x a + C {\displaystyle \int {-dx \over a^{2}+x^{2}}={1 \over a}\operatorname {arccot} {x \over a}+C} {\displaystyle \int {-dx \over a^{2}+x^{2}}={1 \over a}\operatorname {arccot} {x \over a}+C}
∫ d x x x 2 − a 2 = 1 a arcsec ⁡ | x | a + C {\displaystyle \int {dx \over x{\sqrt {x^{2}-a^{2}}}}={1 \over a}\operatorname {arcsec} {|x| \over a}+C} {\displaystyle \int {dx \over x{\sqrt {x^{2}-a^{2}}}}={1 \over a}\operatorname {arcsec} {|x| \over a}+C}
∫ − d x x x 2 − a 2 = 1 a arccsc ⁡ | x | a + C {\displaystyle \int {-dx \over x{\sqrt {x^{2}-a^{2}}}}={1 \over a}\operatorname {arccsc} {|x| \over a}+C} {\displaystyle \int {-dx \over x{\sqrt {x^{2}-a^{2}}}}={1 \over a}\operatorname {arccsc} {|x| \over a}+C}

Fungsi eksponensial

∫ e x d x = e x + C {\displaystyle \int e^{x}\,dx=e^{x}+C} {\displaystyle \int e^{x}\,dx=e^{x}+C}
∫ a x d x = a x ln ⁡ a + C {\displaystyle \int a^{x}\,dx={\frac {a^{x}}{\ln {a}}}+C} {\displaystyle \int a^{x}\,dx={\frac {a^{x}}{\ln {a}}}+C}

Fungsi logaritma

∫ ln ⁡ x d x = x ln ⁡ x − x + C {\displaystyle \int \ln {x}\,dx=x\ln {x}-x+C} {\displaystyle \int \ln {x}\,dx=x\ln {x}-x+C}
∫ b log ⁡ x d x = x ⋅ b log ⁡ x − x ⋅ b log ⁡ e + C {\displaystyle \int \,^{b}\!\log {x}\,dx=x\cdot \,^{b}\!\log x-x\cdot \,^{b}\!\log e+C} {\displaystyle \int \,^{b}\!\log {x}\,dx=x\cdot \,^{b}\!\log x-x\cdot \,^{b}\!\log e+C}

Fungsi trigonometri

Artikel utama: Daftar integral dari fungsi trigonometri
∫ sin ⁡ x d x = − cos ⁡ x + C {\displaystyle \int \sin {x}\,dx=-\cos {x}+C} {\displaystyle \int \sin {x}\,dx=-\cos {x}+C}
∫ cos ⁡ x d x = sin ⁡ x + C {\displaystyle \int \cos {x}\,dx=\sin {x}+C} {\displaystyle \int \cos {x}\,dx=\sin {x}+C}
∫ tan ⁡ x d x = ln ⁡ | sec ⁡ x | + C {\displaystyle \int \tan {x}\,dx=\ln {\left|\sec {x}\right|}+C} {\displaystyle \int \tan {x}\,dx=\ln {\left|\sec {x}\right|}+C}
∫ cot ⁡ x d x = − ln ⁡ | csc ⁡ x | + C {\displaystyle \int \cot {x}\,dx=-\ln {\left|\csc {x}\right|}+C} {\displaystyle \int \cot {x}\,dx=-\ln {\left|\csc {x}\right|}+C}
∫ sec ⁡ x d x = ln ⁡ | sec ⁡ x + tan ⁡ x | + C {\displaystyle \int \sec {x}\,dx=\ln {\left|\sec {x}+\tan {x}\right|}+C} {\displaystyle \int \sec {x}\,dx=\ln {\left|\sec {x}+\tan {x}\right|}+C}
∫ csc ⁡ x d x = − ln ⁡ | csc ⁡ x + cot ⁡ x | + C {\displaystyle \int \csc {x}\,dx=-\ln {\left|\csc {x}+\cot {x}\right|}+C} {\displaystyle \int \csc {x}\,dx=-\ln {\left|\csc {x}+\cot {x}\right|}+C}
∫ sec 2 ⁡ x d x = tan ⁡ x + C {\displaystyle \int \sec ^{2}x\,dx=\tan x+C} {\displaystyle \int \sec ^{2}x\,dx=\tan x+C}
∫ csc 2 ⁡ x d x = − cot ⁡ x + C {\displaystyle \int \csc ^{2}x\,dx=-\cot x+C} {\displaystyle \int \csc ^{2}x\,dx=-\cot x+C}
∫ sec ⁡ x tan ⁡ x d x = sec ⁡ x + C {\displaystyle \int \sec {x}\,\tan {x}\,dx=\sec {x}+C} {\displaystyle \int \sec {x}\,\tan {x}\,dx=\sec {x}+C}
∫ csc ⁡ x cot ⁡ x d x = − csc ⁡ x + C {\displaystyle \int \csc {x}\,\cot {x}\,dx=-\csc {x}+C} {\displaystyle \int \csc {x}\,\cot {x}\,dx=-\csc {x}+C}
∫ sin 2 ⁡ x d x = 1 2 ( x − sin ⁡ x cos ⁡ x ) + C {\displaystyle \int \sin ^{2}x\,dx={\frac {1}{2}}(x-\sin x\cos x)+C} {\displaystyle \int \sin ^{2}x\,dx={\frac {1}{2}}(x-\sin x\cos x)+C}
∫ cos 2 ⁡ x d x = 1 2 ( x + sin ⁡ x cos ⁡ x ) + C {\displaystyle \int \cos ^{2}x\,dx={\frac {1}{2}}(x+\sin x\cos x)+C} {\displaystyle \int \cos ^{2}x\,dx={\frac {1}{2}}(x+\sin x\cos x)+C}
∫ sec 3 ⁡ x d x = 1 2 sec ⁡ x tan ⁡ x + 1 2 ln ⁡ | sec ⁡ x + tan ⁡ x | + C {\displaystyle \int \sec ^{3}x\,dx={\frac {1}{2}}\sec x\tan x+{\frac {1}{2}}\ln |\sec x+\tan x|+C} {\displaystyle \int \sec ^{3}x\,dx={\frac {1}{2}}\sec x\tan x+{\frac {1}{2}}\ln |\sec x+\tan x|+C}
∫ sin n ⁡ x d x = − sin n − 1 ⁡ x cos ⁡ x n + n − 1 n ∫ sin n − 2 ⁡ x d x {\displaystyle \int \sin ^{n}x\,dx=-{\frac {\sin ^{n-1}{x}\cos {x}}{n}}+{\frac {n-1}{n}}\int \sin ^{n-2}{x}\,dx} {\displaystyle \int \sin ^{n}x\,dx=-{\frac {\sin ^{n-1}{x}\cos {x}}{n}}+{\frac {n-1}{n}}\int \sin ^{n-2}{x}\,dx}
∫ cos n ⁡ x d x = cos n − 1 ⁡ x sin ⁡ x n + n − 1 n ∫ cos n − 2 ⁡ x d x {\displaystyle \int \cos ^{n}x\,dx={\frac {\cos ^{n-1}{x}\sin {x}}{n}}+{\frac {n-1}{n}}\int \cos ^{n-2}{x}\,dx} {\displaystyle \int \cos ^{n}x\,dx={\frac {\cos ^{n-1}{x}\sin {x}}{n}}+{\frac {n-1}{n}}\int \cos ^{n-2}{x}\,dx}

Fungsi trigonometri terbalik

Artikel utama: Daftar integral dari fungsi trigonometri terbalik
∫ arcsin ⁡ ( x ) d x = x a r c s i n ( x ) + 1 − x 2 + C {\displaystyle \int \arcsin(x)\,dx=x\,arcsin(x)+{\sqrt {1-x^{2}}}+C} {\displaystyle \int \arcsin(x)\,dx=x\,arcsin(x)+{\sqrt {1-x^{2}}}+C}
∫ arccos ⁡ ( x ) d x = x a r c c o s ( x ) − 1 − x 2 + C {\displaystyle \int \arccos(x)\,dx=x\,arccos(x)-{\sqrt {1-x^{2}}}+C} {\displaystyle \int \arccos(x)\,dx=x\,arccos(x)-{\sqrt {1-x^{2}}}+C}
∫ arctan ⁡ x d x = x arctan ⁡ x − 1 2 ln ⁡ | 1 + x 2 | + C {\displaystyle \int \arctan {x}\,dx=x\,\arctan {x}-{\frac {1}{2}}\ln {\left|1+x^{2}\right|}+C} {\displaystyle \int \arctan {x}\,dx=x\,\arctan {x}-{\frac {1}{2}}\ln {\left|1+x^{2}\right|}+C}
∫ arccot ⁡ x d x = x arccot ⁡ x + 1 2 ln ⁡ | 1 + x 2 | + C {\displaystyle \int \operatorname {arccot} {x}\,dx=x\,\operatorname {arccot} {x}+{\frac {1}{2}}\ln {\left|1+x^{2}\right|}+C} {\displaystyle \int \operatorname {arccot} {x}\,dx=x\,\operatorname {arccot} {x}+{\frac {1}{2}}\ln {\left|1+x^{2}\right|}+C}
∫ arcsec ⁡ ( x ) d x = x arcsec ⁡ ( x ) − ln ⁡ ( | x | + x 2 − 1 ) + C = x arcsec ⁡ ( x ) − arcosh ⁡ | x | + C {\displaystyle \int \operatorname {arcsec}(x)\,dx=x\operatorname {arcsec}(x)\,-\,\ln \left(\left|x\right|+{\sqrt {x^{2}-1}}\right)\,+\,C=x\operatorname {arcsec}(x)-\operatorname {arcosh} |x|+C} {\displaystyle \int \operatorname {arcsec} (x)\,dx=x\operatorname {arcsec} (x)\,-\,\ln \left(\left|x\right|+{\sqrt {x^{2}-1}}\right)\,+\,C=x\operatorname {arcsec} (x)-\operatorname {arcosh} |x|+C}
∫ arccsc ⁡ ( x ) d x = x arccsc ⁡ ( x ) + ln ⁡ ( | x | + x 2 − 1 ) + C = x arccsc ⁡ ( x ) + arcosh ⁡ | x | + C {\displaystyle \int \operatorname {arccsc}(x)\,dx=x\operatorname {arccsc}(x)\,+\,\ln \left(\left|x\right|+{\sqrt {x^{2}-1}}\right)\,+\,C=x\operatorname {arccsc}(x)+\operatorname {arcosh} |x|+C} {\displaystyle \int \operatorname {arccsc} (x)\,dx=x\operatorname {arccsc} (x)\,+\,\ln \left(\left|x\right|+{\sqrt {x^{2}-1}}\right)\,+\,C=x\operatorname {arccsc} (x)+\operatorname {arcosh} |x|+C}

Fungsi hiperbolik

∫ sinh ⁡ x d x = cosh ⁡ x + C {\displaystyle \int \sinh x\,dx=\cosh x+C} {\displaystyle \int \sinh x\,dx=\cosh x+C}
∫ cosh ⁡ x d x = sinh ⁡ x + C {\displaystyle \int \cosh x\,dx=\sinh x+C} {\displaystyle \int \cosh x\,dx=\sinh x+C}
∫ tanh ⁡ x d x = ln ⁡ | cosh ⁡ x | + C {\displaystyle \int \tanh x\,dx=\ln |\cosh x|+C} {\displaystyle \int \tanh x\,dx=\ln |\cosh x|+C}
∫ coth ⁡ x d x = ln ⁡ | sinh ⁡ x | + C {\displaystyle \int \coth x\,dx=\ln |\sinh x|+C} {\displaystyle \int \coth x\,dx=\ln |\sinh x|+C}
∫ sech x d x = arctan ⁡ ( sinh ⁡ x ) + C {\displaystyle \int {\mbox{sech}}\,x\,dx=\arctan(\sinh x)+C} {\displaystyle \int {\mbox{sech}}\,x\,dx=\arctan(\sinh x)+C}
∫ csch x d x = ln ⁡ | tanh ⁡ x 2 | + C {\displaystyle \int {\mbox{csch}}\,x\,dx=\ln \left|\tanh {x \over 2}\right|+C} {\displaystyle \int {\mbox{csch}}\,x\,dx=\ln \left|\tanh {x \over 2}\right|+C}

Fungsi hiperbolik terbalik

∫ arsinh ⁡ x d x = x arsinh ⁡ x − x 2 + 1 + C {\displaystyle \int \operatorname {arsinh} x\,dx=x\operatorname {arsinh} x-{\sqrt {x^{2}+1}}+C} {\displaystyle \int \operatorname {arsinh} x\,dx=x\operatorname {arsinh} x-{\sqrt {x^{2}+1}}+C}
∫ arcosh ⁡ x d x = x arcosh ⁡ x − x 2 − 1 + C {\displaystyle \int \operatorname {arcosh} x\,dx=x\operatorname {arcosh} x-{\sqrt {x^{2}-1}}+C} {\displaystyle \int \operatorname {arcosh} x\,dx=x\operatorname {arcosh} x-{\sqrt {x^{2}-1}}+C}
∫ artanh ⁡ x d x = x artanh ⁡ x + 1 2 log ⁡ ( 1 − x 2 ) + C {\displaystyle \int \operatorname {artanh} x\,dx=x\operatorname {artanh} x+{\frac {1}{2}}\log {(1-x^{2})}+C} {\displaystyle \int \operatorname {artanh} x\,dx=x\operatorname {artanh} x+{\frac {1}{2}}\log {(1-x^{2})}+C}
∫ arcoth d x = x arcoth ⁡ x + 1 2 log ⁡ ( x 2 − 1 ) + C {\displaystyle \int \operatorname {arcoth} \,dx=x\operatorname {arcoth} x+{\frac {1}{2}}\log {(x^{2}-1)}+C} {\displaystyle \int \operatorname {arcoth} \,dx=x\operatorname {arcoth} x+{\frac {1}{2}}\log {(x^{2}-1)}+C}
∫ arsech x d x = x arsech ⁡ x − arctan ⁡ ( x x − 1 1 − x 1 + x ) + C {\displaystyle \int \operatorname {arsech} \,x\,dx=x\operatorname {arsech} x-\arctan {\left({\frac {x}{x-1}}{\sqrt {\frac {1-x}{1+x}}}\right)}+C} {\displaystyle \int \operatorname {arsech} \,x\,dx=x\operatorname {arsech} x-\arctan {\left({\frac {x}{x-1}}{\sqrt {\frac {1-x}{1+x}}}\right)}+C}
∫ arcsch x d x = x arcsch ⁡ x + log ⁡ [ x ( 1 + 1 x 2 + 1 ) ] + C {\displaystyle \int \operatorname {arcsch} \,x\,dx=x\operatorname {arcsch} x+\log {\left[x\left({\sqrt {1+{\frac {1}{x^{2}}}}}+1\right)\right]}+C} {\displaystyle \int \operatorname {arcsch} \,x\,dx=x\operatorname {arcsch} x+\log {\left[x\left({\sqrt {1+{\frac {1}{x^{2}}}}}+1\right)\right]}+C}

Integral lain, yaitu "Sophomore's dream", diyakini berasal dari Johann Bernoulli. Integral tersebut di antaranya

∫ 0 1 x − x d x = ∑ n = 1 ∞ n − n ( = 1 , 29128599706266 … ) ∫ 0 1 x x d x = − ∑ n = 1 ∞ ( − n ) − n ( = 0 , 78343051071213 … ) {\displaystyle {\begin{aligned}\int _{0}^{1}x^{-x}\,dx&=\sum _{n=1}^{\infty }n^{-n}&&(=1,29128599706266\dots )\\\int _{0}^{1}x^{x}\,dx&=-\sum _{n=1}^{\infty }(-n)^{-n}&&(=0,78343051071213\dots )\end{aligned}}} {\displaystyle {\begin{aligned}\int _{0}^{1}x^{-x}\,dx&=\sum _{n=1}^{\infty }n^{-n}&&(=1,29128599706266\dots )\\\int _{0}^{1}x^{x}\,dx&=-\sum _{n=1}^{\infty }(-n)^{-n}&&(=0,78343051071213\dots )\end{aligned}}}

Lihat pula

Referensi

Pustaka

  • M. Abramowitz and I.A. Stegun, editors. Handbook of Mathematical Functions with Formulas, Graphs, and Mathematical Tables.
  • I.S. Gradshteyn (И.С. Градштейн), I.M. Ryzhik (И.М. Рыжик); Alan Jeffrey, Daniel Zwillinger, editors. Table of Integrals, Series, and Products, seventh edition. Academic Press, 2007. ISBN 978-0-12-373637-6. Errata. (Several previous editions as well.)
  • A.P. Prudnikov (А.П. Прудников), Yu.A. Brychkov (Ю.А. Брычков), O.I. Marichev (О.И. Маричев). Integrals and Series. First edition (Russian), volume 1–5, Nauka, 1981−1986. First edition (English, translated from the Russian by N.M. Queen), volume 1–5, Gordon & Breach Science Publishers/CRC Press, 1988–1992, ISBN 2-88124-097-6. Second revised edition (Russian), volume 1–3, Fiziko-Matematicheskaya Literatura, 2003.
  • Yu.A. Brychkov (Ю.А. Брычков), Handbook of Special Functions: Derivatives, Integrals, Series and Other Formulas. Russian edition, Fiziko-Matematicheskaya Literatura, 2006. English edition, Chapman & Hall/CRC Press, 2008, ISBN 1-58488-956-X.
  • Daniel Zwillinger. CRC Standard Mathematical Tables and Formulae, 31st edition. Chapman & Hall/CRC Press, 2002. ISBN 1-58488-291-3. (Many earlier editions as well.)

Sejarah

Pranala luar

Tabel integral

Derivasi

Layanan daring

Program open source

Konten disalin dari Wikipedia Bahasa Indonesia (lisensi CC BY-SA) Lihat versi asli di Wikipedia

Rekomendasi Pilihan