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Lampung Tengah Kebakaran Landa TPA Bandarjaya Lampung Tengah, Gas Metan Diduga Pemicu Utama Pesawaran Pesawaran Jadi Pelopor Lampung, Lantik Pengurus Abpednas di 11 Kecamatan Lampung Tengah Asap Tebal TPA Bandar Jaya Picu Tabrakan Beruntun di Tol Trans-Sumatera, Dua Korban Luka Lampung Prakiraan Cuaca Lampung 19 Oktober 2026: Waspada Hujan Malam Hari Lampung Aktivitas Gunung Anak Krakatau Tetap Siaga, Kegempaan Terus Terjadi Universitas Teknokrat Indonesia Mahasiswa Universitas Teknokrat Raih Empat Gelar Bergengsi di Kompetisi Bahasa Inggris Nasional Pesisir Barat Pesisir Barat Jalin Kemitraan Strategis, Dorong Akses Pendidikan Tinggi Terjangkau Universitas Teknokrat Indonesia Teknokrat dan PMD Pesawaran Bersinergi Wujudkan Desa Digital Berkelanjutan Humaniora Memperkuat Hak Konstitusional Perempuan Adat untuk Kedaulatan Bangsa Pesawaran Lampung Dorong Rantai Pasok Hijau Kakao, Kopi, Lada ke Pasar Global Lampung Tengah Kebakaran Landa TPA Bandarjaya Lampung Tengah, Gas Metan Diduga Pemicu Utama Pesawaran Pesawaran Jadi Pelopor Lampung, Lantik Pengurus Abpednas di 11 Kecamatan Lampung Tengah Asap Tebal TPA Bandar Jaya Picu Tabrakan Beruntun di Tol Trans-Sumatera, Dua Korban Luka Lampung Prakiraan Cuaca Lampung 19 Oktober 2026: Waspada Hujan Malam Hari Lampung Aktivitas Gunung Anak Krakatau Tetap Siaga, Kegempaan Terus Terjadi Universitas Teknokrat Indonesia Mahasiswa Universitas Teknokrat Raih Empat Gelar Bergengsi di Kompetisi Bahasa Inggris Nasional Pesisir Barat Pesisir Barat Jalin Kemitraan Strategis, Dorong Akses Pendidikan Tinggi Terjangkau Universitas Teknokrat Indonesia Teknokrat dan PMD Pesawaran Bersinergi Wujudkan Desa Digital Berkelanjutan Humaniora Memperkuat Hak Konstitusional Perempuan Adat untuk Kedaulatan Bangsa Pesawaran Lampung Dorong Rantai Pasok Hijau Kakao, Kopi, Lada ke Pasar Global
Simetri ikosahedral

Simetri ikosahedral

ikosahedron reguler memiliki 60 simetri rotasi (atau pelestari orientasi), dan urutan simetri sebanyak 120 termasuk transformasi yang menggabungkan refleksi dan rotasi

Bagikan:
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(Pelajari cara dan kapan saatnya untuk menghapus pesan templat ini)
Grup titik dalam tiga dimensi
120px-Sphere_symmetry_group_cs.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Simetri involusi
Cs, (*)
[ ] = CDel_node_c2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
120px-Sphere_symmetry_group_c3v.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Simetri siklik
Cnv, (*nn)
[n] = CDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_n.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
120px-Sphere_symmetry_group_d3h.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Simetri dihedral
Dnh, (*n22)
[n,2] = CDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_n.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Grup polihedral, [n,3], (*n32)
120px-Sphere_symmetry_group_td.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Simetri tetrahedral
Td, (*332)
[3,3] = CDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
120px-Sphere_symmetry_group_oh.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Simetri oktahedral
Oh, (*432)
[4,3] = CDel_node_c2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_4.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
120px-Sphere_symmetry_group_ih.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Simetri ikosahedral
Ih, (*532)
[5,3] = CDel_node_c2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
250px-Icosahedral_reflection_domains.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Domain dasar simetri ikosahedral
250px-Soccer_ball.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Sebuah sepak bola, contoh umum dari bola ikosahedron potongan, memiliki simetri ikosahedral penuh.

Sebuah ikosahedron reguler memiliki 60 simetri rotasi (atau pelestari orientasi), dan urutan simetri sebanyak 120 termasuk transformasi yang menggabungkan refleksi dan rotasi. Sebuah dodecahedron beraturan memiliki himpunan simetri yang sama, karena merupakan ganda dari ikosahedron.

Grup simetri penuh (termasuk refleksi) dikenal juga sebagai grup Coxeter H3, dan diwakili oleh notasi Coxeter [5,3] dan diagram Coxeter CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled. Himpunan simetri orientasi-kekal dalam bentuk subgrup isomorfik pada grup A5 (grup selang-seling pada 5 huruf).

Sebagai titik grup

Terlepas dari dua deret tak hingga dari simetri prismatik dan antiprismatik, simetri ikosahedral rotasi atau simetri ikosahedral kiral dari objek kiral dan simetri ikosahedral penuh atau simetri ikosahedral akiral adalah simetri titik diskret (atau ekuivalen, simetri pada bola) dengan grup simetri terbesar.

Simetri ikosahedral tidak kompatibel dengan simetri translasi, jadi tidak ada grup titik kristalografi atau grup ruang terkait.

Schö. Coxeter Orb. Struktur
abstrak
Orde
I[5,3]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled532A560
Ih[5,3]CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled*532A5×2120

Presentasi yang sesuai dengan di atas adalah:

I : ⟨ s , t ∣ s 2 , t 3 , ( s t ) 5 ⟩   {\displaystyle I:\langle s,t\mid s^{2},t^{3},(st)^{5}\rangle \ } {\displaystyle I:\langle s,t\mid s^{2},t^{3},(st)^{5}\rangle \ }
I h : ⟨ s , t ∣ s 3 ( s t ) − 2 , t 5 ( s t ) − 2 ⟩ .   {\displaystyle I_{h}:\langle s,t\mid s^{3}(st)^{-2},t^{5}(st)^{-2}\rangle .\ } {\displaystyle I_{h}:\langle s,t\mid s^{3}(st)^{-2},t^{5}(st)^{-2}\rangle .\ }

Ini sesuai dengan grup ikosahedral (rotasi dan penuh) sebagai (2,3,5) grup segitiga.

Presentasi pertama diberikan oleh William Rowan Hamilton pada tahun 1856, dalam makalahnya tentang kalkulus ikosian.[1]

Perhatikan bahwa presentasi lain dimungkinkan, misalnya sebagai grup selang-seling (untuk I).

Visualisasi

Schoe.
(Orb.)
Notasi
Coxeter
Elemen Diagram cermin
Ortogonal Proyeksi stereografis
Ih
(*532)
CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
CDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
[5,3]
Garis
cermin:
15 CDel_node_c1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
120px-Spherical_disdyakis_triacontahedron.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail 250px-Disdyakis_triacontahedron_stereographic_d5.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail 250px-Disdyakis_triacontahedron_stereographic_d3.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail 250px-Disdyakis_triacontahedron_stereographic_d2.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
I
(532)
CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Coxeter_diagram_chiral_icosahedral_group.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
[5,3]+
Titik
girasi:
12520px-Patka_piechota.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
20320px-Nazi_concentration_camp_Wehrmacht_red_triangle_badge.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
30220px-Rhomb.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
120px-Sphere_symmetry_group_i.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail 250px-Disdyakis_triacontahedron_stereographic_d5_gyrations.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
20px-Patka_piechota.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
250px-Disdyakis_triacontahedron_stereographic_d3_gyrations.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
20px-Nazi_concentration_camp_Wehrmacht_red_triangle_badge.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
250px-Disdyakis_triacontahedron_stereographic_d2_gyrations.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
20px-Rhomb.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail

Struktur grup

250px-Spherical_compound_of_five_octahedra.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail 250px-Disdyakis_triacontahedron_stereographic_d2_5-color.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Tepi sebuah bola gabungan lima oktahedra mewakili 15 bidang cermin sebagai lingkaran besar berwarna. Setiap oktahedron/segi delapan mewakili 3 bidang cermin ortogonal pada tepinya.
250px-Spherical_compound_of_five_octahedra-pyritohedral_symmetry.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail 250px-Disdyakis_triacontahedron_stereographic_d2_pyritohedral.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Simetri piritohedron adalah subgrup indeks 5 simetri ikosahedral, dengan 3 garis refleksi hijau ortogonal dan 8 titik girasi urutan-3 merah. Ada 5 orientasi yang berbeda dari simetri piritohedron.

Grup rotasi ikosahedral I adalah urutan 60. Grup I adalah isomorfik hingga A5, grup selang-seling dari permutasi genap lima objek. Isomorfisme ini diwujudkan dengan "I" pada berbagai senyawa, terutama majemuk lima kubus (yang tertulis di dodecahedron), gabungan lima oktahedra, atau salah satu dari dua senyawa lima tetrahedra (yaitu enantiomorf, dan tertulis di dodecahedron).

Grup berisi 5 versi Th dengan 20 versi D3 (10 sumbu, 2 per sumbu), dan 6 versi D5.

Grup ikosahedral penuh Ih memiliki urutan 120. Memiliki I sebagai subgrup normal dari indeks 2. Grup Ih isomorfik dengan I × Z2, atau A5 × Z2, dengan inversi di tengah sesuai dengan elemen (identitas,-1), dimana Z2 ditulis secara perkalian.

Ih pada gabungan lima kubus dan gabungan lima oktahedra, namun 1 bertindak sebagai identitas (karena kubus dan oktahedra simetris terpusat). Ia bekerja pada gabungan sepuluh tetrahedra: I pada dua bagian kiral (gabungan dari lima tetrahedra), dan 1 menukar dua bagian. Khususnya, "tidak" bertindak sebagai S5, dan grup ini tidak isomorfik; lihat di bawah untuk detailnya.

Grup ini berisi 10 versi D3d dan 6 versi D5d (simetri seperti antiprisma).

I adalah isomorfik pada PSL2(5), namun Ih tidak isomorfik terhadap SL2(5).

Isomorfisme I dengan A5

Hal ini berguna untuk menggambarkan secara eksplisit seperti apa isomorfisme antara I dan A5. Pada tabel berikut, permutasi Pi dan Qi masing-masing bekerja pada 5 dan 12 elemen, sedangkan matriks rotasi Mi adalah elemen dari I. Jika Pk adalah hasil kali dari permutasi Pi dan menerapkan Pj padanya, maka untuk nilai yang sama dari i, j dan k, juga benar bahwa Qk adalah hasil kali dari pengambilan Qi dan menerapkan Qj, dan juga mengalikan sebuah vektor dengan Mk sama dengan mengalikan vektor tersebut dengan Mi dan kemudian mengalikan hasilnya dengan Mj, yaitu Mk = Mj × Mi. Karena permutasi Pi adalah semua 60 permutasi genap dari 12345, korespondensi satu-ke-satu dibuat eksplisit, oleh karena itu isomorfismenya juga.

Matriks rotasi Permutasi 5
pada 1 2 3 4 5
Permutasi 12
pada 1 2 3 4 5 6 7 8 9 10 11 12
M 1 = [ 1 0 0 0 1 0 0 0 1 ] {\displaystyle M_{1}={\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}}} {\displaystyle M_{1}={\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}}} P 1 {\displaystyle P_{1}} {\displaystyle P_{1}} = () Q 1 {\displaystyle Q_{1}} {\displaystyle Q_{1}} = ()
M 2 = [ − 1 2 1 2 ϕ ϕ 2 − 1 2 ϕ ϕ 2 − 1 2 − ϕ 2 − 1 2 − 1 2 ϕ ] {\displaystyle M_{2}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{2}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 2 {\displaystyle P_{2}} {\displaystyle P_{2}} = (3 4 5) Q 2 {\displaystyle Q_{2}} {\displaystyle Q_{2}} = (1 11 8)(2 9 6)(3 5 12)(4 7 10)
M 3 = [ − 1 2 − 1 2 ϕ − ϕ 2 1 2 ϕ ϕ 2 − 1 2 ϕ 2 − 1 2 − 1 2 ϕ ] {\displaystyle M_{3}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{3}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 3 {\displaystyle P_{3}} {\displaystyle P_{3}} = (3 5 4) Q 3 {\displaystyle Q_{3}} {\displaystyle Q_{3}} = (1 8 11)(2 6 9)(3 12 5)(4 10 7)
M 4 = [ − 1 2 1 2 ϕ − ϕ 2 1 2 ϕ − ϕ 2 − 1 2 − ϕ 2 − 1 2 1 2 ϕ ] {\displaystyle M_{4}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{4}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 4 {\displaystyle P_{4}} {\displaystyle P_{4}} = (2 3)(4 5) Q 4 {\displaystyle Q_{4}} {\displaystyle Q_{4}} = (1 12)(2 8)(3 6)(4 9)(5 10)(7 11)
M 5 = [ ϕ 2 1 2 1 2 ϕ 1 2 − 1 2 ϕ − ϕ 2 − 1 2 ϕ ϕ 2 − 1 2 ] {\displaystyle M_{5}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{5}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 5 {\displaystyle P_{5}} {\displaystyle P_{5}} = (2 3 4) Q 5 {\displaystyle Q_{5}} {\displaystyle Q_{5}} = (1 2 3)(4 5 6)(7 9 8)(10 11 12)
M 6 = [ − 1 2 ϕ − ϕ 2 1 2 ϕ 2 − 1 2 − 1 2 ϕ 1 2 1 2 ϕ ϕ 2 ] {\displaystyle M_{6}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{6}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 6 {\displaystyle P_{6}} {\displaystyle P_{6}} = (2 3 5) Q 6 {\displaystyle Q_{6}} {\displaystyle Q_{6}} = (1 7 5)(2 4 11)(3 10 9)(6 8 12)
M 7 = [ ϕ 2 1 2 − 1 2 ϕ 1 2 − 1 2 ϕ ϕ 2 1 2 ϕ − ϕ 2 − 1 2 ] {\displaystyle M_{7}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{7}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 7 {\displaystyle P_{7}} {\displaystyle P_{7}} = (2 4 3) Q 7 {\displaystyle Q_{7}} {\displaystyle Q_{7}} = (1 3 2)(4 6 5)(7 8 9)(10 12 11)
M 8 = [ 0 − 1 0 0 0 1 − 1 0 0 ] {\displaystyle M_{8}={\begin{bmatrix}0&-1&0\\0&0&1\\-1&0&0\end{bmatrix}}} {\displaystyle M_{8}={\begin{bmatrix}0&-1&0\\0&0&1\\-1&0&0\end{bmatrix}}} P 8 {\displaystyle P_{8}} {\displaystyle P_{8}} = (2 4 5) Q 8 {\displaystyle Q_{8}} {\displaystyle Q_{8}} = (1 10 6)(2 7 12)(3 4 8)(5 11 9)
M 9 = [ − ϕ 2 1 2 1 2 ϕ 1 2 1 2 ϕ ϕ 2 1 2 ϕ ϕ 2 − 1 2 ] {\displaystyle M_{9}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{9}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 9 {\displaystyle P_{9}} {\displaystyle P_{9}} = (2 4)(3 5) Q 9 {\displaystyle Q_{9}} {\displaystyle Q_{9}} = (1 9)(2 5)(3 11)(4 12)(6 7)(8 10)
M 10 = [ − 1 2 ϕ ϕ 2 1 2 − ϕ 2 − 1 2 1 2 ϕ 1 2 − 1 2 ϕ ϕ 2 ] {\displaystyle M_{10}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{10}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 10 {\displaystyle P_{10}} {\displaystyle P_{10}} = (2 5 3) Q 10 {\displaystyle Q_{10}} {\displaystyle Q_{10}} = (1 5 7)(2 11 4)(3 9 10)(6 12 8)
M 11 = [ 0 0 − 1 − 1 0 0 0 1 0 ] {\displaystyle M_{11}={\begin{bmatrix}0&0&-1\\-1&0&0\\0&1&0\end{bmatrix}}} {\displaystyle M_{11}={\begin{bmatrix}0&0&-1\\-1&0&0\\0&1&0\end{bmatrix}}} P 11 {\displaystyle P_{11}} {\displaystyle P_{11}} = (2 5 4) Q 11 {\displaystyle Q_{11}} {\displaystyle Q_{11}} = (1 6 10)(2 12 7)(3 8 4)(5 9 11)
M 12 = [ 1 2 ϕ − ϕ 2 1 2 − ϕ 2 − 1 2 − 1 2 ϕ 1 2 − 1 2 ϕ − ϕ 2 ] {\displaystyle M_{12}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{12}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 12 {\displaystyle P_{12}} {\displaystyle P_{12}} = (2 5)(3 4) Q 12 {\displaystyle Q_{12}} {\displaystyle Q_{12}} = (1 4)(2 10)(3 7)(5 8)(6 11)(9 12)
M 13 = [ 1 0 0 0 − 1 0 0 0 − 1 ] {\displaystyle M_{13}={\begin{bmatrix}1&0&0\\0&-1&0\\0&0&-1\end{bmatrix}}} {\displaystyle M_{13}={\begin{bmatrix}1&0&0\\0&-1&0\\0&0&-1\end{bmatrix}}} P 13 {\displaystyle P_{13}} {\displaystyle P_{13}} = (1 2)(4 5) Q 13 {\displaystyle Q_{13}} {\displaystyle Q_{13}} = (1 3)(2 4)(5 8)(6 7)(9 10)(11 12)
M 14 = [ − 1 2 1 2 ϕ ϕ 2 1 2 ϕ − ϕ 2 1 2 ϕ 2 1 2 1 2 ϕ ] {\displaystyle M_{14}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{14}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 14 {\displaystyle P_{14}} {\displaystyle P_{14}} = (1 2)(3 4) Q 14 {\displaystyle Q_{14}} {\displaystyle Q_{14}} = (1 5)(2 7)(3 11)(4 9)(6 10)(8 12)
M 15 = [ − 1 2 − 1 2 ϕ − ϕ 2 − 1 2 ϕ − ϕ 2 1 2 − ϕ 2 1 2 1 2 ϕ ] {\displaystyle M_{15}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{15}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 15 {\displaystyle P_{15}} {\displaystyle P_{15}} = (1 2)(3 5) Q 15 {\displaystyle Q_{15}} {\displaystyle Q_{15}} = (1 12)(2 10)(3 8)(4 6)(5 11)(7 9)
M 16 = [ − 1 2 − 1 2 ϕ ϕ 2 1 2 ϕ ϕ 2 1 2 − ϕ 2 1 2 − 1 2 ϕ ] {\displaystyle M_{16}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{16}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 16 {\displaystyle P_{16}} {\displaystyle P_{16}} = (1 2 3) Q 16 {\displaystyle Q_{16}} {\displaystyle Q_{16}} = (1 11 6)(2 5 9)(3 7 12)(4 10 8)
M 17 = [ − 1 2 ϕ ϕ 2 − 1 2 ϕ 2 1 2 1 2 ϕ 1 2 − 1 2 ϕ − ϕ 2 ] {\displaystyle M_{17}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{17}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 17 {\displaystyle P_{17}} {\displaystyle P_{17}} = (1 2 3 4 5) Q 17 {\displaystyle Q_{17}} {\displaystyle Q_{17}} = (1 6 5 3 9)(4 12 7 8 11)
M 18 = [ ϕ 2 − 1 2 − 1 2 ϕ 1 2 1 2 ϕ ϕ 2 − 1 2 ϕ − ϕ 2 1 2 ] {\displaystyle M_{18}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{18}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 18 {\displaystyle P_{18}} {\displaystyle P_{18}} = (1 2 3 5 4) Q 18 {\displaystyle Q_{18}} {\displaystyle Q_{18}} = (1 4 8 6 2)(5 7 10 12 9)
M 19 = [ − 1 2 ϕ − ϕ 2 − 1 2 − ϕ 2 1 2 − 1 2 ϕ 1 2 1 2 ϕ − ϕ 2 ] {\displaystyle M_{19}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{19}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 19 {\displaystyle P_{19}} {\displaystyle P_{19}} = (1 2 4 5 3) Q 19 {\displaystyle Q_{19}} {\displaystyle Q_{19}} = (1 8 7 3 10)(2 12 5 6 11)
M 20 = [ 0 0 1 − 1 0 0 0 − 1 0 ] {\displaystyle M_{20}={\begin{bmatrix}0&0&1\\-1&0&0\\0&-1&0\end{bmatrix}}} {\displaystyle M_{20}={\begin{bmatrix}0&0&1\\-1&0&0\\0&-1&0\end{bmatrix}}} P 20 {\displaystyle P_{20}} {\displaystyle P_{20}} = (1 2 4) Q 20 {\displaystyle Q_{20}} {\displaystyle Q_{20}} = (1 7 4)(2 11 8)(3 5 10)(6 9 12)
M 21 = [ 1 2 ϕ ϕ 2 − 1 2 − ϕ 2 1 2 1 2 ϕ 1 2 1 2 ϕ ϕ 2 ] {\displaystyle M_{21}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{21}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 21 {\displaystyle P_{21}} {\displaystyle P_{21}} = (1 2 4 3 5) Q 21 {\displaystyle Q_{21}} {\displaystyle Q_{21}} = (1 2 9 11 7)(3 6 12 10 4)
M 22 = [ ϕ 2 − 1 2 1 2 ϕ 1 2 1 2 ϕ − ϕ 2 1 2 ϕ ϕ 2 1 2 ] {\displaystyle M_{22}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{22}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 22 {\displaystyle P_{22}} {\displaystyle P_{22}} = (1 2 5 4 3) Q 22 {\displaystyle Q_{22}} {\displaystyle Q_{22}} = (2 3 4 7 5)(6 8 10 11 9)
M 23 = [ 0 1 0 0 0 − 1 − 1 0 0 ] {\displaystyle M_{23}={\begin{bmatrix}0&1&0\\0&0&-1\\-1&0&0\end{bmatrix}}} {\displaystyle M_{23}={\begin{bmatrix}0&1&0\\0&0&-1\\-1&0&0\end{bmatrix}}} P 23 {\displaystyle P_{23}} {\displaystyle P_{23}} = (1 2 5) Q 23 {\displaystyle Q_{23}} {\displaystyle Q_{23}} = (1 9 8)(2 6 3)(4 5 12)(7 11 10)
M 24 = [ − ϕ 2 − 1 2 − 1 2 ϕ 1 2 − 1 2 ϕ − ϕ 2 1 2 ϕ − ϕ 2 1 2 ] {\displaystyle M_{24}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{24}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 24 {\displaystyle P_{24}} {\displaystyle P_{24}} = (1 2 5 3 4) Q 24 {\displaystyle Q_{24}} {\displaystyle Q_{24}} = (1 10 5 4 11)(2 8 9 3 12)
M 25 = [ − 1 2 1 2 ϕ − ϕ 2 − 1 2 ϕ ϕ 2 1 2 ϕ 2 1 2 − 1 2 ϕ ] {\displaystyle M_{25}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{25}={\begin{bmatrix}-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 25 {\displaystyle P_{25}} {\displaystyle P_{25}} = (1 3 2) Q 25 {\displaystyle Q_{25}} {\displaystyle Q_{25}} = (1 6 11)(2 9 5)(3 12 7)(4 8 10)
M 26 = [ ϕ 2 1 2 1 2 ϕ − 1 2 1 2 ϕ ϕ 2 1 2 ϕ − ϕ 2 1 2 ] {\displaystyle M_{26}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{26}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 26 {\displaystyle P_{26}} {\displaystyle P_{26}} = (1 3 4 5 2) Q 26 {\displaystyle Q_{26}} {\displaystyle Q_{26}} = (2 5 7 4 3)(6 9 11 10 8)
M 27 = [ − 1 2 ϕ − ϕ 2 1 2 − ϕ 2 1 2 1 2 ϕ − 1 2 − 1 2 ϕ − ϕ 2 ] {\displaystyle M_{27}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{27}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 27 {\displaystyle P_{27}} {\displaystyle P_{27}} = (1 3 5 4 2) Q 27 {\displaystyle Q_{27}} {\displaystyle Q_{27}} = (1 10 3 7 8)(2 11 6 5 12)
M 28 = [ − 1 2 − 1 2 ϕ ϕ 2 − 1 2 ϕ − ϕ 2 − 1 2 ϕ 2 − 1 2 1 2 ϕ ] {\displaystyle M_{28}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{28}={\begin{bmatrix}-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 28 {\displaystyle P_{28}} {\displaystyle P_{28}} = (1 3)(4 5) Q 28 {\displaystyle Q_{28}} {\displaystyle Q_{28}} = (1 7)(2 10)(3 11)(4 5)(6 12)(8 9)
M 29 = [ − 1 2 ϕ ϕ 2 − 1 2 − ϕ 2 − 1 2 − 1 2 ϕ − 1 2 1 2 ϕ ϕ 2 ] {\displaystyle M_{29}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{29}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 29 {\displaystyle P_{29}} {\displaystyle P_{29}} = (1 3 4) Q 29 {\displaystyle Q_{29}} {\displaystyle Q_{29}} = (1 9 10)(2 12 4)(3 6 8)(5 11 7)
M 30 = [ ϕ 2 − 1 2 − 1 2 ϕ − 1 2 − 1 2 ϕ − ϕ 2 1 2 ϕ ϕ 2 − 1 2 ] {\displaystyle M_{30}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{30}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 30 {\displaystyle P_{30}} {\displaystyle P_{30}} = (1 3 5) Q 30 {\displaystyle Q_{30}} {\displaystyle Q_{30}} = (1 3 4)(2 8 7)(5 6 10)(9 12 11)
M 31 = [ − ϕ 2 1 2 − 1 2 ϕ 1 2 1 2 ϕ − ϕ 2 − 1 2 ϕ − ϕ 2 − 1 2 ] {\displaystyle M_{31}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{31}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 31 {\displaystyle P_{31}} {\displaystyle P_{31}} = (1 3)(2 4) Q 31 {\displaystyle Q_{31}} {\displaystyle Q_{31}} = (1 12)(2 6)(3 9)(4 11)(5 8)(7 10)
M 32 = [ 1 2 ϕ − ϕ 2 − 1 2 ϕ 2 1 2 − 1 2 ϕ 1 2 − 1 2 ϕ ϕ 2 ] {\displaystyle M_{32}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{32}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 32 {\displaystyle P_{32}} {\displaystyle P_{32}} = (1 3 2 4 5) Q 32 {\displaystyle Q_{32}} {\displaystyle Q_{32}} = (1 4 10 11 5)(2 3 8 12 9)
M 33 = [ 1 2 1 2 ϕ ϕ 2 1 2 ϕ ϕ 2 − 1 2 − ϕ 2 1 2 1 2 ϕ ] {\displaystyle M_{33}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{33}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 33 {\displaystyle P_{33}} {\displaystyle P_{33}} = (1 3 5 2 4) Q 33 {\displaystyle Q_{33}} {\displaystyle Q_{33}} = (1 5 9 6 3)(4 7 11 12 8)
M 34 = [ 1 2 ϕ ϕ 2 1 2 ϕ 2 − 1 2 1 2 ϕ 1 2 1 2 ϕ − ϕ 2 ] {\displaystyle M_{34}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{34}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 34 {\displaystyle P_{34}} {\displaystyle P_{34}} = (1 3)(2 5) Q 34 {\displaystyle Q_{34}} {\displaystyle Q_{34}} = (1 2)(3 5)(4 9)(6 7)(8 11)(10 12)
M 35 = [ − ϕ 2 − 1 2 1 2 ϕ 1 2 − 1 2 ϕ ϕ 2 − 1 2 ϕ ϕ 2 1 2 ] {\displaystyle M_{35}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{35}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 35 {\displaystyle P_{35}} {\displaystyle P_{35}} = (1 3 2 5 4) Q 35 {\displaystyle Q_{35}} {\displaystyle Q_{35}} = (1 11 2 7 9)(3 10 6 4 12)
M 36 = [ 1 2 − 1 2 ϕ − ϕ 2 1 2 ϕ − ϕ 2 1 2 − ϕ 2 − 1 2 − 1 2 ϕ ] {\displaystyle M_{36}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{36}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 36 {\displaystyle P_{36}} {\displaystyle P_{36}} = (1 3 4 2 5) Q 36 {\displaystyle Q_{36}} {\displaystyle Q_{36}} = (1 8 2 4 6)(5 10 9 7 12)
M 37 = [ ϕ 2 1 2 − 1 2 ϕ − 1 2 1 2 ϕ − ϕ 2 − 1 2 ϕ ϕ 2 1 2 ] {\displaystyle M_{37}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{37}={\begin{bmatrix}{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 37 {\displaystyle P_{37}} {\displaystyle P_{37}} = (1 4 5 3 2) Q 37 {\displaystyle Q_{37}} {\displaystyle Q_{37}} = (1 2 6 8 4)(5 9 12 10 7)
M 38 = [ 0 − 1 0 0 0 − 1 1 0 0 ] {\displaystyle M_{38}={\begin{bmatrix}0&-1&0\\0&0&-1\\1&0&0\end{bmatrix}}} {\displaystyle M_{38}={\begin{bmatrix}0&-1&0\\0&0&-1\\1&0&0\end{bmatrix}}} P 38 {\displaystyle P_{38}} {\displaystyle P_{38}} = (1 4 2) Q 38 {\displaystyle Q_{38}} {\displaystyle Q_{38}} = (1 4 7)(2 8 11)(3 10 5)(6 12 9)
M 39 = [ − ϕ 2 1 2 1 2 ϕ − 1 2 − 1 2 ϕ − ϕ 2 − 1 2 ϕ − ϕ 2 1 2 ] {\displaystyle M_{39}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{39}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 39 {\displaystyle P_{39}} {\displaystyle P_{39}} = (1 4 3 5 2) Q 39 {\displaystyle Q_{39}} {\displaystyle Q_{39}} = (1 11 4 5 10)(2 12 3 9 8)
M 40 = [ − 1 2 ϕ − ϕ 2 − 1 2 ϕ 2 − 1 2 1 2 ϕ − 1 2 − 1 2 ϕ ϕ 2 ] {\displaystyle M_{40}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{40}={\begin{bmatrix}-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 40 {\displaystyle P_{40}} {\displaystyle P_{40}} = (1 4 3) Q 40 {\displaystyle Q_{40}} {\displaystyle Q_{40}} = (1 10 9)(2 4 12)(3 8 6)(5 7 11)
M 41 = [ 0 0 1 1 0 0 0 1 0 ] {\displaystyle M_{41}={\begin{bmatrix}0&0&1\\1&0&0\\0&1&0\end{bmatrix}}} {\displaystyle M_{41}={\begin{bmatrix}0&0&1\\1&0&0\\0&1&0\end{bmatrix}}} P 41 {\displaystyle P_{41}} {\displaystyle P_{41}} = (1 4 5) Q 41 {\displaystyle Q_{41}} {\displaystyle Q_{41}} = (1 5 2)(3 7 9)(4 11 6)(8 10 12)
M 42 = [ 1 2 ϕ ϕ 2 − 1 2 ϕ 2 − 1 2 − 1 2 ϕ − 1 2 − 1 2 ϕ − ϕ 2 ] {\displaystyle M_{42}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{42}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 42 {\displaystyle P_{42}} {\displaystyle P_{42}} = (1 4)(3 5) Q 42 {\displaystyle Q_{42}} {\displaystyle Q_{42}} = (1 6)(2 3)(4 9)(5 8)(7 12)(10 11)
M 43 = [ − ϕ 2 1 2 − 1 2 ϕ − 1 2 − 1 2 ϕ ϕ 2 1 2 ϕ ϕ 2 1 2 ] {\displaystyle M_{43}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{43}={\begin{bmatrix}-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\end{bmatrix}}} P 43 {\displaystyle P_{43}} {\displaystyle P_{43}} = (1 4 5 2 3) Q 43 {\displaystyle Q_{43}} {\displaystyle Q_{43}} = (1 9 7 2 11)(3 12 4 6 10)
M 44 = [ 1 2 ϕ − ϕ 2 − 1 2 − ϕ 2 − 1 2 1 2 ϕ − 1 2 1 2 ϕ − ϕ 2 ] {\displaystyle M_{44}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{44}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 44 {\displaystyle P_{44}} {\displaystyle P_{44}} = (1 4)(2 3) Q 44 {\displaystyle Q_{44}} {\displaystyle Q_{44}} = (1 8)(2 10)(3 4)(5 12)(6 7)(9 11)
M 45 = [ 1 2 1 2 ϕ ϕ 2 − 1 2 ϕ − ϕ 2 1 2 ϕ 2 − 1 2 − 1 2 ϕ ] {\displaystyle M_{45}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{45}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 45 {\displaystyle P_{45}} {\displaystyle P_{45}} = (1 4 2 3 5) Q 45 {\displaystyle Q_{45}} {\displaystyle Q_{45}} = (2 7 3 5 4)(6 11 8 9 10)
M 46 = [ 1 2 1 2 ϕ − ϕ 2 1 2 ϕ ϕ 2 1 2 ϕ 2 − 1 2 1 2 ϕ ] {\displaystyle M_{46}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{46}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 46 {\displaystyle P_{46}} {\displaystyle P_{46}} = (1 4 2 5 3) Q 46 {\displaystyle Q_{46}} {\displaystyle Q_{46}} = (1 3 6 9 5)(4 8 12 11 7)
M 47 = [ 1 2 − 1 2 ϕ ϕ 2 − 1 2 ϕ ϕ 2 1 2 − ϕ 2 − 1 2 1 2 ϕ ] {\displaystyle M_{47}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{47}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 47 {\displaystyle P_{47}} {\displaystyle P_{47}} = (1 4 3 2 5) Q 47 {\displaystyle Q_{47}} {\displaystyle Q_{47}} = (1 7 10 8 3)(2 5 11 12 6)
M 48 = [ − 1 0 0 0 1 0 0 0 − 1 ] {\displaystyle M_{48}={\begin{bmatrix}-1&0&0\\0&1&0\\0&0&-1\end{bmatrix}}} {\displaystyle M_{48}={\begin{bmatrix}-1&0&0\\0&1&0\\0&0&-1\end{bmatrix}}} P 48 {\displaystyle P_{48}} {\displaystyle P_{48}} = (1 4)(2 5) Q 48 {\displaystyle Q_{48}} {\displaystyle Q_{48}} = (1 12)(2 9)(3 11)(4 10)(5 6)(7 8)
M 49 = [ − 1 2 ϕ ϕ 2 1 2 ϕ 2 1 2 − 1 2 ϕ − 1 2 1 2 ϕ − ϕ 2 ] {\displaystyle M_{49}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{49}={\begin{bmatrix}-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\end{bmatrix}}} P 49 {\displaystyle P_{49}} {\displaystyle P_{49}} = (1 5 4 3 2) Q 49 {\displaystyle Q_{49}} {\displaystyle Q_{49}} = (1 9 3 5 6)(4 11 8 7 12)
M 50 = [ 0 0 − 1 1 0 0 0 − 1 0 ] {\displaystyle M_{50}={\begin{bmatrix}0&0&-1\\1&0&0\\0&-1&0\end{bmatrix}}} {\displaystyle M_{50}={\begin{bmatrix}0&0&-1\\1&0&0\\0&-1&0\end{bmatrix}}} P 50 {\displaystyle P_{50}} {\displaystyle P_{50}} = (1 5 2) Q 50 {\displaystyle Q_{50}} {\displaystyle Q_{50}} = (1 8 9)(2 3 6)(4 12 5)(7 10 11)
M 51 = [ 1 2 ϕ − ϕ 2 1 2 ϕ 2 1 2 1 2 ϕ − 1 2 1 2 ϕ ϕ 2 ] {\displaystyle M_{51}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{51}={\begin{bmatrix}{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 51 {\displaystyle P_{51}} {\displaystyle P_{51}} = (1 5 3 4 2) Q 51 {\displaystyle Q_{51}} {\displaystyle Q_{51}} = (1 7 11 9 2)(3 4 10 12 6)
M 52 = [ ϕ 2 − 1 2 1 2 ϕ − 1 2 − 1 2 ϕ ϕ 2 − 1 2 ϕ − ϕ 2 − 1 2 ] {\displaystyle M_{52}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{52}={\begin{bmatrix}{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 52 {\displaystyle P_{52}} {\displaystyle P_{52}} = (1 5 3) Q 52 {\displaystyle Q_{52}} {\displaystyle Q_{52}} = (1 4 3)(2 7 8)(5 10 6)(9 11 12)
M 53 = [ 0 1 0 0 0 1 1 0 0 ] {\displaystyle M_{53}={\begin{bmatrix}0&1&0\\0&0&1\\1&0&0\end{bmatrix}}} {\displaystyle M_{53}={\begin{bmatrix}0&1&0\\0&0&1\\1&0&0\end{bmatrix}}} P 53 {\displaystyle P_{53}} {\displaystyle P_{53}} = (1 5 4) Q 53 {\displaystyle Q_{53}} {\displaystyle Q_{53}} = (1 2 5)(3 9 7)(4 6 11)(8 12 10)
M 54 = [ − ϕ 2 − 1 2 − 1 2 ϕ − 1 2 1 2 ϕ ϕ 2 − 1 2 ϕ ϕ 2 − 1 2 ] {\displaystyle M_{54}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{54}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 54 {\displaystyle P_{54}} {\displaystyle P_{54}} = (1 5)(3 4) Q 54 {\displaystyle Q_{54}} {\displaystyle Q_{54}} = (1 12)(2 11)(3 10)(4 8)(5 9)(6 7)
M 55 = [ 1 2 ϕ ϕ 2 1 2 − ϕ 2 1 2 − 1 2 ϕ − 1 2 − 1 2 ϕ ϕ 2 ] {\displaystyle M_{55}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} {\displaystyle M_{55}={\begin{bmatrix}{\frac {1}{2\phi }}&{\frac {\phi }{2}}&{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\\-{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\end{bmatrix}}} P 55 {\displaystyle P_{55}} {\displaystyle P_{55}} = (1 5 4 2 3) Q 55 {\displaystyle Q_{55}} {\displaystyle Q_{55}} = (1 5 11 10 4)(2 9 12 8 3)
M 56 = [ − ϕ 2 − 1 2 1 2 ϕ − 1 2 1 2 ϕ − ϕ 2 1 2 ϕ − ϕ 2 − 1 2 ] {\displaystyle M_{56}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} {\displaystyle M_{56}={\begin{bmatrix}-{\frac {\phi }{2}}&-{\frac {1}{2}}&{\frac {1}{2\phi }}\\-{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\end{bmatrix}}} P 56 {\displaystyle P_{56}} {\displaystyle P_{56}} = (1 5)(2 3) Q 56 {\displaystyle Q_{56}} {\displaystyle Q_{56}} = (1 10)(2 12)(3 11)(4 7)(5 8)(6 9)
M 57 = [ 1 2 − 1 2 ϕ − ϕ 2 − 1 2 ϕ ϕ 2 − 1 2 ϕ 2 1 2 1 2 ϕ ] {\displaystyle M_{57}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{57}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&{\frac {1}{2\phi }}\end{bmatrix}}} P 57 {\displaystyle P_{57}} {\displaystyle P_{57}} = (1 5 2 3 4) Q 57 {\displaystyle Q_{57}} {\displaystyle Q_{57}} = (1 3 8 10 7)(2 6 12 11 5)
M 58 = [ 1 2 1 2 ϕ − ϕ 2 − 1 2 ϕ − ϕ 2 − 1 2 − ϕ 2 1 2 − 1 2 ϕ ] {\displaystyle M_{58}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{58}={\begin{bmatrix}{\frac {1}{2}}&{\frac {1}{2\phi }}&-{\frac {\phi }{2}}\\-{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\-{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 58 {\displaystyle P_{58}} {\displaystyle P_{58}} = (1 5 2 4 3) Q 58 {\displaystyle Q_{58}} {\displaystyle Q_{58}} = (1 6 4 2 8)(5 12 7 9 10)
M 59 = [ 1 2 − 1 2 ϕ ϕ 2 1 2 ϕ − ϕ 2 − 1 2 ϕ 2 1 2 − 1 2 ϕ ] {\displaystyle M_{59}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} {\displaystyle M_{59}={\begin{bmatrix}{\frac {1}{2}}&-{\frac {1}{2\phi }}&{\frac {\phi }{2}}\\{\frac {1}{2\phi }}&-{\frac {\phi }{2}}&-{\frac {1}{2}}\\{\frac {\phi }{2}}&{\frac {1}{2}}&-{\frac {1}{2\phi }}\end{bmatrix}}} P 59 {\displaystyle P_{59}} {\displaystyle P_{59}} = (1 5 3 2 4) Q 59 {\displaystyle Q_{59}} {\displaystyle Q_{59}} = (2 4 5 3 7)(6 10 9 8 11)
M 60 = [ − 1 0 0 0 − 1 0 0 0 1 ] {\displaystyle M_{60}={\begin{bmatrix}-1&0&0\\0&-1&0\\0&0&1\end{bmatrix}}} {\displaystyle M_{60}={\begin{bmatrix}-1&0&0\\0&-1&0\\0&0&1\end{bmatrix}}} P 60 {\displaystyle P_{60}} {\displaystyle P_{60}} = (1 5)(2 4) Q 60 {\displaystyle Q_{60}} {\displaystyle Q_{60}} = (1 11)(2 10)(3 12)(4 9)(5 7)(6 8)

Grup biasa limbung

Semua grup berikut memiliki urutan 120, tetapi tidak isomorfik:

Ia sesuai dengan urutan tepat pendek berikut (yang terakhir tidak terpecah) dan produk

1 → A 5 → S 5 → Z 2 → 1 {\displaystyle 1\to A_{5}\to S_{5}\to Z_{2}\to 1} {\displaystyle 1\to A_{5}\to S_{5}\to Z_{2}\to 1}
I h = A 5 × Z 2 {\displaystyle I_{h}=A_{5}\times Z_{2}} {\displaystyle I_{h}=A_{5}\times Z_{2}}
1 → Z 2 → 2 I → A 5 → 1 {\displaystyle 1\to Z_{2}\to 2I\to A_{5}\to 1} {\displaystyle 1\to Z_{2}\to 2I\to A_{5}\to 1}

In words,

  • A 5 {\displaystyle A_{5}} {\displaystyle A_{5}} adalah subgrup normal dari S 5 {\displaystyle S_{5}} {\displaystyle S_{5}}
  • A 5 {\displaystyle A_{5}} {\displaystyle A_{5}} adalah faktor dari I h {\displaystyle I_{h}} {\displaystyle I_{h}}, yang merupakan produk langsung
  • A 5 {\displaystyle A_{5}} {\displaystyle A_{5}} adalah grup hasil bagi dari 2 I {\displaystyle 2I} {\displaystyle 2I}

Perhatikan bahwa A 5 {\displaystyle A_{5}} {\displaystyle A_{5}} memiliki biasa 3 dimensi representasi yang tidak direduksi (sebagai grup rotasi ikosahedral), namun S 5 {\displaystyle S_{5}} {\displaystyle S_{5}} tidak memiliki representasi 3 dimensi yang tidak dapat direduksi, sesuai dengan grup ikosahedral penuh tidak sebagai grup simetris.

Ini juga dikaitkan dengan grup linear atas Medan hingga dengan lima elemen, yang menunjukkan subgrup dan grup penutup secara langsung; tidak satupun dari ini adalah grup ikosahedral penuh:

Kelas konjugasi

120 simetri terbagi dalam 10 kelas konjugasi.

Kelas konjugasi
I Kelas penjumlahan Ih
  • identitas, urutan 1
  • 12 × rotasi sebesar ±72°, urutan 5, mengelilingi 6 sumbu melalui pusat muka dodecahedron
  • 12 × rotasi sebesar ±144°, urutan 5, mengelilingi 6 sumbu melalui pusat muka dodecahedron
  • 20 × rotasi dengan ±120°, urutan 3, sekitar 10 sumbu melalui simpul dari dodecahedron
  • 15 × rotasi 180°, urutan 2, sekitar 15 sumbu melalui titik tengah tepi dodecahedron
  • inversi pusat, urutan 2
  • 12 × rotorefleksi sebesar ±36°, urutan 10, di sekitar 6 sumbu melalui pusat muka dodecahedron
  • 12 × rotorefleksi sebesar ±108°, urutan 10, di sekitar 6 sumbu melalui pusat muka dodecahedron
  • 20 × rotorefleksi sebesar ±60°, orde 6, di sekitar 10 sumbu melalui simpul dodecahedron
  • 15 × refleksi, urutan 2, pada 15 bidang melalui tepi dodecahedron

Subgrup dari grup simetri ikosahedral penuh

330px-Icosahedral_subgroup_tree.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Relasi subgrup
250px-Chiral_icosahedral_subgroup_tree.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Relasi subgrup kiral

Setiap baris dalam tabel berikut mewakili satu kelas subgrup konjugat (yaitu, ekuivalen secara geometris). Kolom "Banyak." (multiplisitas) memberikan jumlah subgrup yang berbeda di kelas konjugasi. Penjelasan warna: hijau = grup yang dihasilkan oleh refleksi, merah = grup kiral (pelestarian orientasi), yang hanya berisi rotasi.

Grup tersebut digambarkan secara geometris dalam bentuk dodecahedron. Singkatan "s.p.m.t.(tepi)" berarti "setengah putaran menukar tepi ini dengan tepi berlawanan", dan juga untuk "wajah" dan "simpul".

Schön.CoxeterOrb.H-MStrukturSiklus.Urutan|IndeksMult.Deskripsi
Ih[5,3]CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled*532532/mA5×Z212011grup penuh
D2h[2,2]CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled*222mmmDih2×Dih1=Dih1340px-GroupDiagramMiniC2x3.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail8155memperbaiki dua sisi berlawanan, dengan menukarnya
C5v[5]CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled*555mDih525px]]10126memperbaiki wajah
C3v[3]CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled*333mDih3=S340px-GroupDiagramMiniD6.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail62010memperbaiki simpul
C2v[2]CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled*222mmDih2=Dih1240px-GroupDiagramMiniD4.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail43015memperbaiki tepi
Cs[ ]CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled*2 atau mDih140px-GroupDiagramMiniC2.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail26015refleksi menukar dua titik akhir dari sebuah tepi
Th[3+,4]CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_4.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled3*2m3A4×Z240px-GroupDiagramMiniA4xC2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail2455grup piritohedral
D5d[2+,10]CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_10.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled2*510m2Dih10=Z2×Dih540px-GroupDiagramMiniD20.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail2066memperbaiki dua wajah berlawanan, dengan menukarnya
D3d[2+,6]CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_6.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled2*33mDih6=Z2×Dih340px-GroupDiagramMiniD12.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail121010memperbaiki dua simpul berlawanan, dengan menukarnya
D1d = C2h[2+,2]CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled2*2/mDih2=Z2×Dih140px-GroupDiagramMiniD4.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail43015setengah putaran di sekitar titik tengah tepi, ditambah inversi pusat
S10[2+,10+]CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h4.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_10.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled5×5Z10=Z2×Z540px-GroupDiagramMiniC10.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail10126rotasi wajah, ditambah inversi pusat
S6[2+,6+]CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h4.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_6.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled3×3Z6=Z2×Z340px-GroupDiagramMiniC6.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail62010rotasi tentang simpul, ditambah inversi pusat
S2[2+,2+]CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h4.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled×1Z240px-GroupDiagramMiniC2.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail2601inversi pusat
I[5,3]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled532532A56021semua rotasi
T[3,3]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled332332A440px-GroupDiagramMiniA4.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail12105rotasi dari tetrahedron terhubung
D5[2,5]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled522522Dih540px-GroupDiagramMiniD10.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail10126rotasi di sekitar pusat wajah, dan s.p.m.t.(wajah)
D3[2,3]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled322322Dih3=S340px-GroupDiagramMiniD6.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail62010rotasi di sekitar simpul, dan s.p.m.t.(titik)
D2[2,2]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled222222Dih2=Z2240px-GroupDiagramMiniD4.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail43015setengah berputar di sekitar titik tengah tepi, dan s.p.m.t.(tepi)
C5[5]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled555Z540px-GroupDiagramMiniC5.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail5246rotasi di sekitar pusat wajah
C3[3]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled333Z3=A340px-GroupDiagramMiniC3.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail34010rotasi di sekitar simpul
C2[2]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2x.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled222Z240px-GroupDiagramMiniC2.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail26015setengah putaran titik tengah tepi
C1[ ]+CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled111Z140px-GroupDiagramMiniC1.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail11201grup trivial

Stabilisator titik

Stabilisator dari pasangan simpul berlawanan diartikan sebagai stabilisator dari sumbu yang dihasilkan.

  • stabilisator titik di I memberikan grup siklik C3
  • stabilisator titik di Ih memberikan grup dihedral D3
  • stabilisator dari pasangan simpul berlawanan di I memberikan grup dihedral D3
  • stabilisator dari pasangan simpul berlawanan di Ih memberikan D 3 × ± 1 {\displaystyle D_{3}\times \pm 1} {\displaystyle D_{3}\times \pm 1}

Stabilisator tepi

Stabilisator dari sepasang tepi berlawanan diartikan sebagai stabilisator persegi panjang yang dihasilkan.

  • stabilisator tepi di I memberikan grup siklik Z2
  • penstabil tepi di Ih memberikan Klein empat grup Z 2 × Z 2 {\displaystyle Z_{2}\times Z_{2}} {\displaystyle Z_{2}\times Z_{2}}
  • stabilisator dari sepasang sisi dalam I memberikan Klein empat grup Z 2 × Z 2 {\displaystyle Z_{2}\times Z_{2}} {\displaystyle Z_{2}\times Z_{2}}; 5 diantaranya, diberikan oleh rotasi 180° dalam 3 sumbu tegak lurus.
  • stabilisator dari sepasang sisi dalam Ih memberikan Z 2 × Z 2 × Z 2 {\displaystyle Z_{2}\times Z_{2}\times Z_{2}} {\displaystyle Z_{2}\times Z_{2}\times Z_{2}}; 5 diantaranya, yang diberikan oleh refleksi dalam 3 sumbu tegak lurus.

Stabilisator wajah

Stabilisator dari pasangan wajah berlawanan diartikan sebagai stabilisator anti-prisma yang dihasilkan.

  • stabilisator wajah di I memberikan grup siklik C5
  • stabilisator wajah di Ih memberikan grup dihedral D5
  • stabilisator dari pasangan wajah berlawanan di I memberikan grup dihedral D5
  • stabilisator dari pasangan wajah yang berlawanan di Ih memberikan D 5 × ± 1 {\displaystyle D_{5}\times \pm 1} {\displaystyle D_{5}\times \pm 1}

Stabilisator polihedron

Untuk masing-masing, 5 salinan konjugasi, dan tindakan konjugasi memberikan peta, I → ∼ A 5 < S 5 {\displaystyle I{\stackrel {\sim }{\to }}A_{5}<S_{5}} {\displaystyle I{\stackrel {\sim }{\to }}A_{5}<S_{5}}.

  • stabilisator dari tetrahedra tertulis di I adalah salinan T
  • stabilisator dari tetrahedra tertulis di Ih adalah salinan T
  • stabilisator dari kubus tertulis (atau pasangan berlawanan dari tetrahedra, atau oktahedra) di I adalah salinan T
  • stabilisator dari kubus tertulis (atau pasangan berlawanan dari tetrahedra, atau oktahedra) di Ih adalah salinan dari Th

Generator grup Coxeter

Grup simetri ikosahedral penuh [5,3] (CDel_node_n0.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_n1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_n2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled) urutan 120 memiliki generator diwakili oleh matriks refleksi R0, R1, R2, dengan relasi R02 = R12 = R22 = (R0×R1)5 = (R1×R2)3 = (R0×R2)2 = Identitas. Grup [5,3]+ (CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled) urutan 60 dihasilkan oleh dua rotasi S0,1, S1,2, S0,2. Sebuah refleksi rotor urutan 10 dihasilkan oleh V0,1,2, produk dari ketiga refleksi. Di sini ϕ = 5 + 1 2 {\displaystyle \phi ={\tfrac {{\sqrt {5}}+1}{2}}} {\displaystyle \phi ={\tfrac {{\sqrt {5}}+1}{2}}} menunjukkan rasio emas.

[5,3], CDel_node_n0.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_n1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_n2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Refleksi Rotasi Rotorefleksi
Nama R0 R1 R2 S0,1 S1,2 S0,2 V0,1,2
Grup CDel_node_n0.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled CDel_node_n1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled CDel_node_n2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled CDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_10.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h4.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Urutan 22253210
Matrix [ − 1 0 0 0 1 0 0 0 1 ] {\displaystyle \left[{\begin{smallmatrix}-1&0&0\\0&1&0\\0&0&1\end{smallmatrix}}\right]} {\displaystyle \left[{\begin{smallmatrix}-1&0&0\\0&1&0\\0&0&1\end{smallmatrix}}\right]} [ 1 − ϕ 2 − ϕ 2 − 1 2 − ϕ 2 1 2 1 − ϕ 2 − 1 2 1 − ϕ 2 ϕ 2 ] {\displaystyle \left[{\begin{smallmatrix}{\frac {1-\phi }{2}}&{\frac {-\phi }{2}}&{\frac {-1}{2}}\\{\frac {-\phi }{2}}&{\frac {1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {1-\phi }{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]} {\displaystyle \left[{\begin{smallmatrix}{\frac {1-\phi }{2}}&{\frac {-\phi }{2}}&{\frac {-1}{2}}\\{\frac {-\phi }{2}}&{\frac {1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {1-\phi }{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]} [ 1 0 0 0 − 1 0 0 0 1 ] {\displaystyle \left[{\begin{smallmatrix}1&0&0\\0&-1&0\\0&0&1\end{smallmatrix}}\right]} {\displaystyle \left[{\begin{smallmatrix}1&0&0\\0&-1&0\\0&0&1\end{smallmatrix}}\right]} [ ϕ − 1 2 ϕ 2 1 2 − ϕ 2 1 2 1 − ϕ 2 − 1 2 1 − ϕ 2 ϕ 2 ] {\displaystyle \left[{\begin{smallmatrix}{\frac {\phi -1}{2}}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {-\phi }{2}}&{\frac {1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {1-\phi }{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]} {\displaystyle \left[{\begin{smallmatrix}{\frac {\phi -1}{2}}&{\frac {\phi }{2}}&{\frac {1}{2}}\\{\frac {-\phi }{2}}&{\frac {1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {1-\phi }{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]} [ 1 − ϕ 2 ϕ 2 − 1 2 − ϕ 2 − 1 2 1 − ϕ 2 − 1 2 ϕ − 1 2 ϕ 2 ] {\displaystyle \left[{\begin{smallmatrix}{\frac {1-\phi }{2}}&{\frac {\phi }{2}}&{\frac {-1}{2}}\\{\frac {-\phi }{2}}&{\frac {-1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {\phi -1}{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]} {\displaystyle \left[{\begin{smallmatrix}{\frac {1-\phi }{2}}&{\frac {\phi }{2}}&{\frac {-1}{2}}\\{\frac {-\phi }{2}}&{\frac {-1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {\phi -1}{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]} [ − 1 0 0 0 − 1 0 0 0 1 ] {\displaystyle \left[{\begin{smallmatrix}-1&0&0\\0&-1&0\\0&0&1\end{smallmatrix}}\right]} {\displaystyle \left[{\begin{smallmatrix}-1&0&0\\0&-1&0\\0&0&1\end{smallmatrix}}\right]} [ ϕ − 1 2 − ϕ 2 1 2 − ϕ 2 − 1 2 1 − ϕ 2 − 1 2 ϕ − 1 2 ϕ 2 ] {\displaystyle \left[{\begin{smallmatrix}{\frac {\phi -1}{2}}&{\frac {-\phi }{2}}&{\frac {1}{2}}\\{\frac {-\phi }{2}}&{\frac {-1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {\phi -1}{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]} {\displaystyle \left[{\begin{smallmatrix}{\frac {\phi -1}{2}}&{\frac {-\phi }{2}}&{\frac {1}{2}}\\{\frac {-\phi }{2}}&{\frac {-1}{2}}&{\frac {1-\phi }{2}}\\{\frac {-1}{2}}&{\frac {\phi -1}{2}}&{\frac {\phi }{2}}\end{smallmatrix}}\right]}
(1,0,0)n ( ϕ 2 , 1 2 , ϕ − 1 2 ) {\displaystyle ({\begin{smallmatrix}{\frac {\phi }{2}},{\frac {1}{2}},{\frac {\phi -1}{2}}\end{smallmatrix}})} {\displaystyle ({\begin{smallmatrix}{\frac {\phi }{2}},{\frac {1}{2}},{\frac {\phi -1}{2}}\end{smallmatrix}})}n (0,1,0)n ( 0 , − 1 , ϕ ) {\displaystyle (0,-1,\phi )} {\displaystyle (0,-1,\phi )}sumbu ( 1 − ϕ , 0 , ϕ ) {\displaystyle (1-\phi ,0,\phi )} {\displaystyle (1-\phi ,0,\phi )}sumbu ( 0 , 0 , 1 ) {\displaystyle (0,0,1)} {\displaystyle (0,0,1)}sumbu

Domain fundamental

Domain fundamental untuk grup rotasi ikosahedral dan grup ikosahedral penuh diberikan oleh:

250px-Sphere_symmetry_group_i.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Grup rotasi ikosahedral
I
250px-Sphere_symmetry_group_ih.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Grup ikosahedral penuh
Ih
250px-Disdyakistriacontahedron.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Wajah triacontahedron Disdyakis adalah domain fundamental

Dalam triacontahedron Disdyakis satu wajah penuh adalah domain fundamental; padatan lain dengan simetri yang sama diperoleh dengan menyesuaikan orientasi wajah, misalnya himpunan bagian wajah dipilih untuk menggabungkan setiap himpunan bagian menjadi satu wajah, atau mengganti setiap wajah dengan beberapa wajah, atau permukaan melengkung.

Polihedra dengan simetri ikosahedral

Informasi lebih lanjut: Padatan dengan simetri ikosahedral

Kiral polihedra

Kelas Simbol Gambar
Archimedean sr{5,3}
CDel_node_h.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_h.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-Snubdodecahedronccw.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Catalan V3.3.3.3.5
CDel_node_fh.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_fh.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_fh.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-Pentagonalhexecontahedronccw.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail

Simetri ikosahedral penuh

Padatan PlatonisPolihedra Kepler–Poinsot Padatan Archimedean
60px-Dodecahedron.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
{5,3}
CDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:SmallStellatedDodecahedron.svg
{5/2,5}
CDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5-2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:GreatStellatedDodecahedron.svg
{5/2,3}
CDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5-2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:TruncatedDodecahedron.svg
t{5,3}
CDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-Truncatedicosahedron.svg.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
t{3,5}
CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:IcosiDodecahedron.svg
r{3,5}
CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:RhombicosiDodecahedron.svg
rr{3,5}
CDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:TruncatedicosiDodecahedron.svg
tr{3,5}
CDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Padatan PlatonikPolihedra Kepler–Poinsot Padatan Catalan
60px-Icosahedron.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
{3,5}
CDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled = CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:GreatDodecahedron.svg
{5,5/2}
CDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5-2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled = CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5-2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-GreatIcosahedron.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
{3,5/2}
CDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5-2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled = CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5-2.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-Triakisicosahedron.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
V3.10.10
CDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
Berkas:PentakisDodecahedron.svg
V5.6.6
CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-Rhombictriacontahedron.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
V3.5.3.5
CDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-Deltoidalhexecontahedron.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
V3.4.5.4
CDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled
60px-Disdyakistriacontahedron.jpg?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
V4.6.10
CDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_5.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_3.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaledCDel_node_f1.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail_unscaled

Objek lain dengan simetri ikosahedral

Contoh simetri ikosahedral
250px-Adenovirus_3D_schematic.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Kapsid dari Adenovirus
250px-Dodecaborate%2812%29-dianion-from-xtal-3D-bs-17.png?utm_source=id.wikipedia.org&utm_campaign=parser&utm_content=thumbnail
Ion dodecaborate [B12H12]2−

Kristal cair dengan simetri ikosahedral

Untuk fase bahan antara yang disebut kristal cair keberadaan simetri ikosahedral diusulkan oleh H. Kleinert dan K. Maki[2] dan strukturnya pertama kali dianalisis secara rinci dalam makalah itu. Lihat artikel ulasan disini. Dalam aluminium, struktur ikosahedral ditemukan secara eksperimental tiga tahun setelah ini oleh Dan Shechtman, yang membuatnya mendapatkan Hadiah Nobel pada tahun 2011.

Geometri terkait

Simetri ikosahedral setara dengan grup linear khusus proyeksi PSL(2,5), dan adalah grup simetri dari kurva modular X(5), dan lebih umum PSL(2,p) adalah grup simetri dari kurva modular X(p). Kurva modular X(5) secara geometris merupakan dodecahedron dengan titik puncak di tengah setiap wajah poligonal, yang menunjukkan grup simetri.

Geometri ini, dan grup simetri terkait, dipelajari oleh Felix Klein sebagai kelompok monodromi permukaan Belyi – permukaan Riemann dengan peta holomorfik ke bola Riemann, bercabang hanya 0, 1, dan tak hingga (sebuah fungsi Belyi) – puncaknya adalah titik-titik yang terletak atas tak hingga, sedangkan simpul dan pusat setiap tepi terletak di atas 0 dan 1; tingkat penutup (jumlah lembar) sama dengan 5.

Ini muncul dari usahanya untuk memberikan pengaturan geometris mengapa simetri ikosahedral muncul dalam solusi persamaan kuintik, dengan teori yang diberikan dalam (Klein 1888) yang terkenal; eksposisi modern diberikan dalam (Tóth 2002, Bagian 1.6, Topik Tambahan: Teori Klein tentang Ikosahedron, p. 66).

Penyelidikan Klein dilanjutkan dengan penemuan simetri urutan 7 dan urutan 11 dalam (Klein & 1878/79b) harv error: tanpa target: CITEREFKlein1878/79b (bantuan) dan (Klein 1879) (dan penutup terkait derajat 7 dan 11) dan dessins d'enfants, yang pertama menghasilkan kuintik Klein, geometri yang terkait memiliki ubin dengan 24 segi enam (dengan titik puncak di tengah).

Geometri serupa dengan PSL(2,n) dan grup yang umum untuk kurva modular lainnya.

Lebih eksotis lagi, relasi khusus antara grup PSL(2,5) (urutan 60), PSL(2,7) (urutan 168) dan PSL(2,11) (urutan 660), yang juga menerima interpretasi geometris – PSL(2,5) adalah simetri ikosahedron (genus 0), PSL(2,7) dari Klein quartic (genus 3), dan PSL(2,11) permukaan bukminsterfulerena (genus 70). Kelompok-kelompok ini membentuk "trinitas" dalam arti Vladimir Arnold, yang memberikan kerangka kerja untuk berbagai hubungan; lihat trinitas untuk detailnya.

Ada hubungan dekat dengan padatan Platonis lainnya.

Lihat pula

Referensi

Pranala luar

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